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add block hash calculations
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68
coins/monero/src/block/merkle_root.rs
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68
coins/monero/src/block/merkle_root.rs
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@@ -0,0 +1,68 @@
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use crate::hash;
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/// Round to power of two, for count>=3 and for count being not too large (<= 2^28)
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/// (as reasonable for tree hash calculations)
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///
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fn tree_hash_cnt(count: usize) -> usize {
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// This algo has some bad history but all we are doing is 1 << floor(log2(count))
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// There are _many_ ways to do log2, for some reason the one selected was the most obscure one,
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// and fixing it made it even more obscure.
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//
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// Iterative method implemented below aims for clarity over speed, if performance is needed
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// then my advice is to use the BSR instruction on x86
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//
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// All the paranoid asserts have been removed since it is trivial to mathematically prove that
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// the return will always be a power of 2.
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// Problem space has been defined as 3 <= count <= 2^28. Of course quarter of a billion
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// transactions is not a sane upper limit for a block, so there will be tighter limits
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// in other parts of the code
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assert!(count >= 3); // cases for 0,1,2 are handled elsewhere
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assert!(count <= 0x10000000); // sanity limit to 2^28, MSB=1 will cause an inf loop
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let mut pow = 2_usize;
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while pow < count {
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pow <<= 1
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}
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pow >> 1
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}
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fn hash_concat(a: [u8; 32], b: [u8; 32]) -> [u8; 32] {
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let mut v = [a, b].concat();
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hash(&v)
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}
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/// Compute tree hash as defined by Cryptonote
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pub fn tree_hash(root_hash: [u8; 32], extra_hashes: &[[u8; 32]]) -> [u8; 32] {
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match extra_hashes.len() {
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0 => root_hash,
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1 => hash_concat(root_hash, extra_hashes[0]),
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other => {
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let count = other + 1;
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let mut cnt = tree_hash_cnt(count);
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let mut hashes =
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std::iter::once(root_hash).chain(extra_hashes.iter().copied()).collect::<Vec<_>>();
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let mut i = 2 * cnt - count;
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let mut j = 2 * cnt - count;
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while j < cnt {
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hashes[j] = hash_concat(hashes[i], hashes[i + 1]);
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i += 2;
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j += 1;
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}
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assert_eq!(i, count);
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while cnt > 2 {
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cnt >>= 1;
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for i in 0 .. cnt {
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hashes[i] = hash_concat(hashes[2 * i], hashes[2 * i + 1]);
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}
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}
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hash_concat(hashes[0], hashes[1])
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}
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}
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}
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